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Question 89
Find dpdq\frac { d p } { d q }dqdp if p=ln(7q2−3q) p = \ln \left( \frac { 7 q ^ { 2 } - 3 } { q } \right) p=ln(q7q2−3)
A) 7q2−3q(7q2−3) \frac { 7 q ^ { 2 } - 3 } { q \left( 7 q ^ { 2 } - 3 \right) }q(7q2−3) 7q2−3 B) 7q2+3q(7q2−3) \frac { 7 q ^ { 2 } + 3 } { q \left( 7 q ^ { 2 } - 3 \right) }q(7q2−3) 7q2+3 C) 14q2+3q(7q2−3) \frac { 14 q ^ { 2 } + 3 } { q \left( 7 q ^ { 2 } - 3 \right) }q(7q2−3) 14q2+3 D) 14q2−3q(7q2−3) \frac { 14 q ^ { 2 } - 3 } { q \left( 7 q ^ { 2 } - 3 \right) }q(7q2−3) 14q2−3 E) 14q2+7q(7q2−3) \frac { 14 q ^ { 2 } + 7 } { q \left( 7 q ^ { 2 } - 3 \right) }q(7q2−3) 14q2+7
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