Find the limit: $\lim _ { x \rightarrow 11 ^ { + } } \frac { x - 2 } { x - 11 }$ .
A) $- \infty$
B) $\infty$
C)0
D)-1
E)1

Question

Quizplus · Accepted Answer

As $x$ approaches 11 from the right (i.e., values slightly larger than 11), the numerator $x - 2$ becomes a positive number slightly larger than 9. The denominator $x - 11$ becomes a very small positive number since we are approaching 11 from the right. Dividing a positive number by a very small positive number yields a very large positive number, hence the limit is $\infty$.

Find the Limit lim⁡x→11+x−2x−11\lim _ { x \rightarrow 11 ^ { + } } \frac { x - 2 } { x - 11 }limx→11+​x−11x−2​

Find the Limit $\lim _ { x \rightarrow 11 ^ { + } } \frac { x - 2 } { x - 11 }$