Determine which ordered pair is a solution of the system. $\left\{ \begin{array} { c }
x + 4 y ^ { 2 } = 28 \
- x + y = 5
\end{array} \right.$
A)(-8, -3)
B)(-8, 7)
C)(-8, -2)
D)(-3, 8)
E)(-8, 3)

Question

Determine which ordered pair is a solution of the system. $\left\{ \begin{array} { c } 
x + 4 y ^ { 2 } = 28 \
- x + y = 5
\end{array} \right.$
A)(-8, -3)
B)(-8, 7)
C)(-8, -2)
D)(-3, 8)
E)(-8, 3)

Quizplus · Accepted Answer

To find the solution, we can solve the system of equations. From the second equation, we can express $x$ in terms of $y$: $x = y - 5$. Substituting this into the first equation gives $y - 5 + 4y^2 = 28$. Substituting the $x$ and $y$ values from each option into the original equations, only option A, $(-8, -3)$, satisfies both equations.

Determine Which Ordered Pair Is a Solution of the System {x+4y2=28−x+y=5\left\{ \begin{array} { c } x + 4 y ^ { 2 } = 28 \\- x + y = 5\end{array} \right.{x+4y2=28−x+y=5​

Determine Which Ordered Pair Is a Solution of the System $\left\{ \begin{array} { c } x + 4 y ^ { 2 } = 28 \\- x + y = 5\end{array} \right.$