Solve the system by the method of substitution. $\left\{ \begin{array} { l }
- \frac { 1 } { 2 } x + \frac { 1 } { 8 } y = 1 \\
- \frac { 1 } { 3 } x + \frac { 1 } { 6 } y = 1
\end{array} \right.$
A)(-1, -4)
B)(4, -1)
C)(-4, -1)
D)(-1, 4)
E)(1, -4)

Question

Solve the system by the method of substitution. $\left\{ \begin{array} { l } 
- \frac { 1 } { 2 } x + \frac { 1 } { 8 } y = 1 \\
- \frac { 1 } { 3 } x + \frac { 1 } { 6 } y = 1
\end{array} \right.$
A)(-1, -4)
B)(4, -1)
C)(-4, -1)
D)(-1, 4)
E)(1, -4)

Quizplus · Accepted Answer

The Answer of Solve the system by the method of substitution. $\left\{ \begin{array} { l } 
- \frac { 1 } { 2 } x + \frac { 1 } { 8 } y = 1 \\
- \frac { 1 } { 3 } x + \frac { 1 } { 6 } y = 1
\end{array} \right.$
A)(-1, -4)
B)(4, -1)
C)(-4, -1)
D)(-1, 4)
E)(1, -4)

Solve the System by the Method of Substitution {−12x+18y=1−13x+16y=1\left\{ \begin{array} { l } - \frac { 1 } { 2 } x + \frac { 1 } { 8 } y = 1 \\\\- \frac { 1 } { 3 } x + \frac { 1 } { 6 } y = 1\end{array} \right.⎩⎨⎧​−21​x+81​y=1−31​x+61​y=1​

Solve the System by the Method of Substitution $\left\{ \begin{array} { l } - \frac { 1 } { 2 } x + \frac { 1 } { 8 } y = 1 \\\\- \frac { 1 } { 3 } x + \frac { 1 } { 6 } y = 1\end{array} \right.$