Use a graphing utility to find the point(s) of intersection of the graphs. $\left\{ \begin{aligned}
y & = e ^ { x + 2 } \
x - y + 3 & = 0
\end{aligned} \right.$
A) $( - 1 , - 2 )$
B) $( - 1,2 )$
C) $( - 2,1 )$
D) $( - 2 , - 1 )$
E) $( 1,2 )$

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The Answer of Use a graphing utility to find the point(s) of intersection of the graphs. $\left\{ \begin{aligned}
y & = e ^ { x + 2 } \
x - y + 3 & = 0
\end{aligned} \right.$
A) $( - 1 , - 2 )$
B) $( - 1,2 )$
C) $( - 2,1 )$
D) $( - 2 , - 1 )$
E) $( 1,2 )$

Use a Graphing Utility to Find the Point(s) of Intersection {y=ex+2x−y+3=0\left\{ \begin{aligned}y & = e ^ { x + 2 } \\x - y + 3 & = 0\end{aligned} \right.{yx−y+3​=ex+2=0​

Use a Graphing Utility to Find the Point(s) of Intersection $\left\{ \begin{aligned}y & = e ^ { x + 2 } \\x - y + 3 & = 0\end{aligned} \right.$