Solve the system by elimination. $\left\{ \begin{array} { c }
6 x + 8 y = 1 \
- 4 x - 3 y = - 14
\end{array} \right.$
A) $\left( 1 , - \frac { 5 } { 8 } \right)$
B) $\left( 3 , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 109 } { 14 } , - \frac { 40 } { 7 } \right)$
D) $\left( a , \frac { 1 - 6 a } { 8 } \right) \text { (dependent) }$
E)inconsistent

Question

Solve the system by elimination. $\left\{ \begin{array} { c } 
6 x + 8 y = 1 \
- 4 x - 3 y = - 14
\end{array} \right.$
A) $\left( 1 , - \frac { 5 } { 8 } \right)$
B) $\left( 3 , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 109 } { 14 } , - \frac { 40 } { 7 } \right)$
D) $\left( a , \frac { 1 - 6 a } { 8 } \right) \text { (dependent) }$
E)inconsistent

Quizplus · Accepted Answer

The Answer of Solve the system by elimination. $\left\{ \begin{array} { c } 
6 x + 8 y = 1 \
- 4 x - 3 y = - 14
\end{array} \right.$
A) $\left( 1 , - \frac { 5 } { 8 } \right)$
B) $\left( 3 , \frac { 2 } { 3 } \right)$
C) $\left( \frac { 109 } { 14 } , - \frac { 40 } { 7 } \right)$
D) $\left( a , \frac { 1 - 6 a } { 8 } \right) \text { (dependent) }$
E)inconsistent

Solve the System by Elimination {6x+8y=1−4x−3y=−14\left\{ \begin{array} { c } 6 x + 8 y = 1 \\- 4 x - 3 y = - 14\end{array} \right.{6x+8y=1−4x−3y=−14​

Solve the System by Elimination $\left\{ \begin{array} { c } 6 x + 8 y = 1 \\- 4 x - 3 y = - 14\end{array} \right.$