Rewrite the exponential equation $3 ^ { - 2 } = \frac { 1 } { 9 }$ in logarithmic form.
A) $\log _ { 3 } \frac { 1 } { 9 } = - 2$
B) $\log _ { 2 } 9 = - 2$
C) $\log _ { 3 } 9 = - 2$
D) $\log _ { 9 } 3 = - 2$
E) $\log _ { 3 } \frac { 1 } { 9 } = 2$

Question

Quizplus · Accepted Answer

The logarithmic form of $3^{-2} = \frac{1}{9}$ is $\log_{3}\frac{1}{9} = -2$, where 3 is the base, $\frac{1}{9}$ is the argument, and -2 is the exponent.

Rewrite the Exponential Equation 3−2=193 ^ { - 2 } = \frac { 1 } { 9 }3−2=91​

Rewrite the Exponential Equation $3 ^ { - 2 } = \frac { 1 } { 9 }$