Subtract and simplify.
-$\begin{array} { r }
13 \frac { 2 } { 15 } \\
- \quad 7 \frac { 2 } { 9 }
\end{array}$
A) $4 \frac { 41 } { 45 }$
B)5
C) $5 \frac { 41 } { 45 }$
D) $6 \frac { 43 } { 45 }$

Question

Subtract and simplify.
-$\begin{array} { r } 
13 \frac { 2 } { 15 } \\
- \quad 7 \frac { 2 } { 9 }
\end{array}$
A) $4 \frac { 41 } { 45 }$
B)5
C) $5 \frac { 41 } { 45 }$
D) $6 \frac { 43 } { 45 }$

Quizplus · Accepted Answer

To subtract these mixed numbers, first convert them to improper fractions: $13 \frac{2}{15} = \frac{197}{15}$ and $7 \frac{2}{9} = \frac{65}{9}$. To subtract, find a common denominator, which is 135. Convert both fractions: $\frac{197}{15} = \frac{787}{135}$ and $\frac{65}{9} = \frac{585}{135}$. Subtracting gives $\frac{787}{135} - \frac{585}{135} = \frac{202}{135}$, which simplifies to $1 \frac{67}{135}$. However, this needs to be added to the whole number part, resulting in $5 \frac{41}{45}$.

Subtract and Simplify 13215−729\begin{array} { r } 13 \frac { 2 } { 15 } \\\\- \quad 7 \frac { 2 } { 9 }\end{array}13152​−792​​

Subtract and Simplify $\begin{array} { r } 13 \frac { 2 } { 15 } \\\\- \quad 7 \frac { 2 } { 9 }\end{array}$