Find the prime factorization of the number. Write any repeated factors using exponents.
-90
A)2 ·3 ·5
B) $2 \cdot 3 ^ { 2 } \cdot 5$
C) $10 \cdot 3 ^ { 2 }$
D) $2 ^ { 2 } \cdot 3 ^ { 2 } \cdot 5$

Question

Quizplus · Accepted Answer

The prime factorization of 90 is $2 \cdot 3^2 \cdot 5$. Breaking down 90, we get 90 = 2 x 45, and 45 can be further broken down into 3 x 15, and 15 into 3 x 5, resulting in the prime factors 2, 3, 3, and 5. Using exponents for the repeated factor, we get $2 \cdot 3^2 \cdot 5$.

Find the Prime Factorization of the Number 2⋅32⋅52 \cdot 3 ^ { 2 } \cdot 52⋅32⋅5

Find the Prime Factorization of the Number $2 \cdot 3 ^ { 2 } \cdot 5$