Determine the vertex of the graph of the parabola.
-$y = x ^ { 2 } - 4 x + 5$
A)3, 4
B)(2, 1)
C)(2, -1)
D)(2, -4)

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $(-b/2a, f(-b/2a))$. For $y = x^2 - 4x + 5$, $a = 1$, $b = -4$, and $c = 5$. Thus, the x-coordinate of the vertex is $-(-4)/(2*1) = 2$. Plugging $x = 2$ back into the equation gives $y = (2)^2 - 4(2) + 5 = 4 - 8 + 5 = 1$. Therefore, the vertex is $(2, 1)$.

Determine the Vertex of the Graph of the Parabola y=x2−4x+5y = x ^ { 2 } - 4 x + 5y=x2−4x+5

Determine the Vertex of the Graph of the Parabola $y = x ^ { 2 } - 4 x + 5$