Solve the problem.
-Find the area of a triangle with a base of 8x inches and a height of (4x + 2)inches.
A)(16x + 8)sq. in.
B) $\left( 32 x ^ { 2 } + 16 x \right) \text { sq. in. }$
C)( $\left( 16 x ^ { 2 } + 8 x \right) \text { sq. in. }$
D) $\left( 12 x ^ { 2 } + 10 x \right) \text { sq. in. }$

Question

Quizplus · Accepted Answer

The area of a triangle is given by the formula $ \frac{1}{2} \times \text{base} \times \text{height} $. Substituting the given values, we get $ \frac{1}{2} \times 8x \times (4x + 2) = 4x \times (4x + 2) = 16x^2 + 8x $ square inches.

Solve the Problem (32x2+16x) sq. in. \left( 32 x ^ { 2 } + 16 x \right) \text { sq. in. }(32x2+16x) sq. in.

Solve the Problem $\left( 32 x ^ { 2 } + 16 x \right) \text { sq. in. }$