Solve. Assume the exercise describes a linear relationship. When writing a linear equation, write the equation in
slope-intercept form.
-The average value of a certain type of automobile was $15,600 in 1993 and depreciated to $5640 in 1997. Let y be the average value of the automobile in the year x, where x = 0 represents 1993. Write a linear equation that
Models the value of the automobile in terms of the year x.
A)y = -2490x + 5640
B)y = $- \frac { 1 } { 2490 }$ x x- 5640
C)y = -2490x + 15,600
D)y = -2490x - 4320

Question

Quizplus · Accepted Answer

The depreciation from 1993 to 1997 is $15,600 - $5,640 = $9,960 over 4 years, which is $9,960 / 4 = $2,490 per year. Thus, the slope (rate of depreciation) is -$2,490. Since x = 0 corresponds to 1993, when the value was $15,600, the y-intercept is $15,600. Therefore, the equation is y = -2490x + 15,600.

Solve Assume the Exercise Describes a Linear Relationship −12490- \frac { 1 } { 2490 }−24901​

Solve Assume the Exercise Describes a Linear Relationship $- \frac { 1 } { 2490 }$