The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distribution of incomes is skewed to the right. Find the mean and standard error of the mean for
This sampling distribution when using random samples of size 66. Round your answers to the nearest dollar.

Question

Quizplus · Accepted Answer

We use the formula:
Standard error of the mean = standard deviation / sqrt(sample size)
Standard error of the mean = 5600 / sqrt(66)
Standard error of the mean = $689 (rounded to the nearest dollar)

The mean of the sampling distribution is the same as the mean of the population, which is given as $28,520. Therefore, choice A is the best answer. The mean of the sampling distribution of the mean can be found using the same value as the population mean, which is $28,520. 
The standard error of the mean (SE) can be found using the formula: SE = σ/√n, where σ is the population standard deviation and n is the sample size. Substituting the given values, we get SE = 5600/√66 ≈ $689. Therefore, the correct answer is A.

The Mean Annual Income for Adult Women in One City