Write the equation in exponential form.
-$\log _ { 1 / 2 } \left( \frac { 1 } { 8 } \right) = 3$
A) $\left( \frac { 1 } { 2 } \right) ^ { 1 / 8 } = 3$
B) $\left( \frac { 1 } { 2 } \right) ^ { 3 } = \frac { 1 } { 8 }$
C) $\left( \frac { 1 } { 8 } \right) ^ { 3 } = \frac { 1 } { 2 }$
D) $3 ^ { 1 / 2 } = \frac { 1 } { 8 }$

Question

Write the equation in exponential form.
-$\log _ { 1 / 2 } \left( \frac { 1 } { 8 } \right) = 3$ 
A) $\left( \frac { 1 } { 2 } \right) ^ { 1 / 8 } = 3$
B) $\left( \frac { 1 } { 2 } \right) ^ { 3 } = \frac { 1 } { 8 }$
C) $\left( \frac { 1 } { 8 } \right) ^ { 3 } = \frac { 1 } { 2 }$
D) $3 ^ { 1 / 2 } = \frac { 1 } { 8 }$

Quizplus · Accepted Answer

The exponential form of a logarithm $\log_b(a) = c$ is $b^c = a$. Here, $b = \frac{1}{2}$, $a = \frac{1}{8}$, and $c = 3$, so the correct exponential form is $\left(\frac{1}{2}\right)^3 = \frac{1}{8}$.

Write the Equation in Exponential Form log⁡1/2(18)=3\log _ { 1 / 2 } \left( \frac { 1 } { 8 } \right) = 3log1/2​(81​)=3

Write the Equation in Exponential Form $\log _ { 1 / 2 } \left( \frac { 1 } { 8 } \right) = 3$