Find the solution to the system of equations by substitution.
-$$\begin{array} { l }
x + 2 y + 5 z = 10 \
5 y + 4 z = 19 \
z = 1
\end{array}$$
A)(-1, 3, 1)
B)(1, 3, -1)
C)(3, -1, 1)
D)(-1, 1, 3)

Question

Find the solution to the system of equations by substitution.
-$$\begin{array} { l } 
x + 2 y + 5 z = 10 \
5 y + 4 z = 19 \
z = 1
\end{array}$$
A)(-1, 3, 1)
B)(1, 3, -1)
C)(3, -1, 1)
D)(-1, 1, 3)

Quizplus · Accepted Answer

Given $z = 1$, substitute $z$ into the second equation to find $y$: $5y + 4(1) = 19$, which simplifies to $5y = 15$, so $y = 3$. Then, substitute $y$ and $z$ into the first equation to find $x$: $x + 2(3) + 5(1) = 10$, which simplifies to $x + 6 + 5 = 10$, so $x = -1$. Therefore, the solution is $(-1, 3, 1)$.

Find the Solution to the System of Equations by Substitution x+2y+5z=105y+4z=19z=1\begin{array} { l } x + 2 y + 5 z = 10 \\5 y + 4 z = 19 \\z = 1\end{array}x+2y+5z=105y+4z=19z=1​

Find the Solution to the System of Equations by Substitution $\begin{array} { l } x + 2 y + 5 z = 10 \\5 y + 4 z = 19 \\z = 1\end{array}$