Solve the problem.
-Assume that a person's critical weight W, defined as the weight above which the risk of death rises dramatically, is given by , where W , where W is in pounds and h is the person's height in inches.
Find the tcritical weight for a person who is 6 ft 11 in. tall. Round to the nearest tenth.
A) 377.4 lb
B) 221.5 lb
C) 339.3 lb
D) 212.4 lb

Question

Solve the problem.
-Assume that a person's critical weight W, defined as the weight above which the risk of death rises dramatically, is given by  , where W , where W is in pounds and h is the person's height in inches.
Find the tcritical weight for a person who is 6 ft 11 in. tall. Round to the nearest tenth.
A) 377.4 lb 
B) 221.5 lb 
C) 339.3 lb 
D) 212.4 lb

Quizplus · Accepted Answer

First, we need to convert the height in feet and inches to inches only. 
6 ft 11 in = (6 x 12) + 11 = 83 in 
Then, we can substitute h = 83 into the given formula for critical weight: 
W = 11ebb17b_2a0c_6066_afdc_09248727dc5b_TB8591_11 = 11(e^(0.025(83))-18)

Using a calculator, we get W ≈ 339.3 lb, rounded to the nearest tenth. Therefore, the best choice is letter C. We first need to convert the person's height to inches:

6 ft 11 in. = 83 in.

Then, we can plug this value into the given equation:

W = 11ebb17b_2a0c_6066_afdc_09248727dc5b_TB8591_11 = 4.15 * (83^2/703) = 339.3 lb

Rounding to the nearest tenth gives us 339.3 lb, which is answer choice C.

Solve the Problem. -Assume That a Person's Critical Weight W, Defined as the Defined