Solve the problem.
-A freight train traveled at a speed of 50 mph for 3 hours, then stayed in a station for 1 hour, and then traveled 30 mph for 2 hours. Make a graph of distance traveled versus time to match the given situation.

Question

Quizplus · Accepted Answer

The distance the train travels during each segment is given by:

Distance = Speed x Time

For the first segment:

Distance = 50 mph x 3 hours = 150 miles

For the second segment:

Distance = 0 mph x 1 hour = 0 miles (since the train is stationary)

For the third segment:

Distance = 30 mph x 2 hours = 60 miles

Therefore, the total distance traveled by the train is:

150 miles + 0 miles + 60 miles = 210 miles

To graph this, we can plot distance on the y-axis and time on the x-axis. The graph should have a horizontal line at y = 150 from 0 to 3 on the x-axis, then a horizontal line at y = 150 from 4 to 5 on the x-axis, and finally a line with a slope of 30 from y = 150 to y = 210 from 6 to 8 on the x-axis.

Option B matches this graph.

Solve the Problem. -A Freight Train Traveled at a Speed of 50 Mph