Solve the problem.
-If a spring stretches 0.6 meter when a 3-kilogram weight is attached to it, how much will it stretch when an 8-kilogram weight is attached to it?
A)1.6 m
B)0.6 m
C)4.6 m
D)3.6 m

Question

Quizplus · Accepted Answer

We can use the formula for Hooke's Law to solve the problem:

F = kx

where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Since the spring stretches 0.6 meter when a 3-kilogram weight is attached to it, we can find the spring constant as:

F = mg = (3 kg)(9.8 m/s^2) = 29.4 N

k = F/x = 29.4 N/0.6 m = 49 N/m

Using the same formula, we can find how much the spring will stretch when an 8-kilogram weight is attached:

F = mg = (8 kg)(9.8 m/s^2) = 78.4 N

x = F/k = 78.4 N/49 N/m = 1.6 m

Therefore, the spring will stretch 1.6 meters when an 8-kilogram weight is attached to it. The answer is A.

Solve the Problem. -If a Spring Stretches 0.6 Meter When a 3-Kilogram Weight