Solve.
-Two cars leave an intersection. One car travels north; the other east. When the car traveling north had gone 15 mi, the distance between the cars was 5 mi more than the distance traveled by the car heading east. How far had
The eastbound car traveled?
A)25 mi
B)20 mi
C)15 mi
D)30 mi

Question

Quizplus · Accepted Answer

Let x be the distance traveled by the eastbound car. 
Using the Pythagorean theorem, we can set up the equation: 
(15)^2 + (x)^2 = (x+5)^2 
225 + x^2 = x^2 + 10x + 25 
200 = 10x 
x = 20

Therefore, the eastbound car had traveled 20 miles. Let's call the distance traveled by the eastbound car "x". Using the Pythagorean theorem, we know that the distance between the two cars is the square root of (15^2 + x^2). We also know that this distance is 5 more than x. So, we can set up the equation:
square root of (15^2 + x^2) = x + 5
Squaring both sides, we get:
225 + x^2 = x^2 + 10x + 25
Simplifying, we get:
10x = 200
x = 20
Therefore, the distance traveled by the eastbound car is 20 miles.

Solve. -Two Cars Leave an Intersection. One Car Travels North; the the Other