Solve.
-An express and local train leave GraysLake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
A)Express's rate = 50 mph and local's rate = 25 mph.
B)Express's rate = 25 mph and local's rate = 12.5 mph.
C)Express's rate = 60 mph and local's rate = 30 mph.
D)Cannot be determined with information given.

Question

Quizplus · Accepted Answer

The express train's speed is twice the local train's speed, and it arrives 1 hour earlier. If the local train's speed is x, then the express train's speed is 2x. The time difference between their arrivals is 1 hour, which can be represented by the equation: $ \frac{50}{x} - \frac{50}{2x} = 1 $. Solving this equation gives x = 25 mph for the local train and 2x = 50 mph for the express train.

Solve. -An Express and Local Train Leave GraysLake at 3 P.M