Consider the reaction: 4 NH ₃ + 5 O ₂ → 6 H ₂ O + 4 NO
If 125.0 g of NH₃ reacts with 225.0 g of O₂, what is the limiting reagent?

Question

Consider the reaction: 4 NH ₃ + 5 O ₂ → 6 H ₂ O + 4 NO If 125.0 g of NH₃ reacts with 225.0 g of O₂, what is the limiting reagent?

Quizplus · Accepted Answer

To determine the limiting reagent, we need to first convert the given masses of reactants to moles. Moles of NH₃ = 125.0 g / 17.03 g/mol = 7.33 mol Moles of O₂ = 225.0 g / 32.00 g/mol = 7.03 mol Next, we need to determine the limiting reagent using the mole ratio of the reactants from the balanced equation: 4 NH₃ + 5 O₂ → 4 NO + 6 H₂O Mole ratio of NH₃ to O₂ = 4/5 Since the mole ratio is less than 1, this means that there are not enough moles of O₂ to react with all of the moles of NH₃. Therefore, O₂ is the limiting reagent.

Consider the Reaction: 4 NH 3 + 5 O

Consider the Reaction: 4 NH ₃ + 5 O