A 70% alcohol solution is to be mixed with a 46% alcohol solution. How many liters of the 46% alcohol solution should be used to make 40 liters of a 52% alcohol solution?
A) 10 liters
B) 30 liters
C) 40 liters
D) 29 liters

Question

Quizplus · Accepted Answer

Let x be the amount of 46% solution needed.
The amount of alcohol in the 70% solution is 0.7(40-x).
The amount of alcohol in the 46% solution is 0.46x.
The amount of alcohol in the final mixture is 0.52(40).
0.7(40-x) + 0.46x = 0.52(40)
28 - 0.7x + 0.46x = 20.8
0.24x = 7.2
x = 30
Therefore, 30 liters of the 46% solution should be used.

A 70% Alcohol Solution Is to Be Mixed with a 46