Divide $20 x ^ { 2 } - 7 x - 1$ by $4 x + 5$ .
A) $5 x - 8 + \frac { 39 } { 4 x + 5 }$
B) $5 x - 8 + \frac { 35 } { 4 x + 5 }$
C) $5 x - 8 + \frac { 37 } { 4 x + 5 }$
D) $5 x - 7 + \frac { 38 } { 4 x + 5 }$
E) $5 x - 7 + \frac { 36 } { 4 x + 5 }$

Question

Quizplus · Accepted Answer

To divide $20x^2 - 7x - 1$ by $4x + 5$, we can use polynomial long division or synthetic division. The quotient is $5x - 8$ with a remainder of $39$. Therefore, the complete division is $5x - 8 + \frac{39}{4x + 5}$.

Divide 20x2−7x−120 x ^ { 2 } - 7 x - 120x2−7x−1

Divide $20 x ^ { 2 } - 7 x - 1$