Solve: $x ^ { 2 } + x - 30 \geq 0$
A) $[ - 6,5 ]$
B) $( - \infty , - 6 ] \cup [ 5 , \infty )$
C) $( - \infty , - 5 ] \cup [ 6 , \infty )$
D) $[ 5 , \infty )$

Question

Quizplus · Accepted Answer

To solve the quadratic inequality $x^2 + x - 30 \geq 0$, first factor the quadratic equation $x^2 + x - 30 = 0$. Factoring gives $(x + 6)(x - 5) = 0$, so the roots are $x = -6$ and $x = 5$. The inequality is satisfied for $x \leq -6$ and $x \geq 5$, hence the solution is $(-\infty, -6] \cup [5, \infty)$.

Solve x2+x−30≥0x ^ { 2 } + x - 30 \geq 0x2+x−30≥0

Solve $x ^ { 2 } + x - 30 \geq 0$