$O P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \theta$ A calculator is set in the Engineering mode. The display shows: 56.345 -03. Express this value in the proper engineering units.
A) 56.345 micro
B) 56.345 milli
C) 5.6345 milli
D) 563.45 milli

Question

Quizplus · Accepted Answer

The value on the calculator is 56.345 × 10^(-3), which is equivalent to 56.345 milli. This is the proper engineering unit for the given value.

OP=V12+V22+2(V1)(V2)cos⁡θO P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \thetaOP=V12​+V22​+2(V1​)(V2​)cosθ

$O P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \theta$