The septic tank that exists on the property is $6$ ft $\times 3$ ft $\times 3$ ft deep. How many gallons of water will this tank hold? (Water weights 62.4 lb/ $\mathrm { ft } ^ { 3 }$ , and 1 gal of water weights 8.34 lb).
A) 404.0
B) 1,123.2
C) 1,058.7
D) 416.2
E) 877.7

Question

The septic tank that exists on the property is $6$ ft $\times 3$ ft $\times 3$ ft deep. How many gallons of water will this tank hold? (Water weights 62.4 lb/ $\mathrm { ft } ^ { 3 }$ ,  and 1 gal of water weights 8.34 lb).
A) 404.0
B) 1,123.2
C) 1,058.7
D) 416.2
E) 877.7

Quizplus · Accepted Answer

The volume of the septic tank is calculated by multiplying its dimensions: $6 \text{ ft} \times 3 \text{ ft} \times 3 \text{ ft} = 54 \text{ cubic feet}$. To convert cubic feet to gallons, we use the weight of water per cubic foot and per gallon. Since $1 \text{ cubic foot} = 62.4 \text{ lb}$ and $1 \text{ gallon} = 8.34 \text{ lb}$, we find the total weight of water the tank can hold: $54 \text{ cubic feet} \times 62.4 \text{ lb/cubic foot} = 3369.6 \text{ lb}$. Dividing by the weight per gallon gives the volume in gallons: $3369.6 \text{ lb} / 8.34 \text{ lb/gallon} \approx 404.0 \text{ gallons}$.

The Septic Tank That Exists on the Property Is 666 Ft ×3\times 3×3

The Septic Tank That Exists on the Property Is $6$ Ft $\times 3$