Solve, using the substitution method, and check. $\begin{array} { c }
2 y + 7 x = 68 \
y = 3 x - 18
\end{array}$
A) (-8, -6)
B) (8, 6)
C) (13, 1)
D) (9, 5)
E) (11, 3)

Question

Solve, using the substitution method, and check. $\begin{array} { c } 
2 y + 7 x = 68 \
y = 3 x - 18
\end{array}$
A) (-8, -6)
B) (8, 6)
C) (13, 1)
D) (9, 5)
E) (11, 3)

Quizplus · Accepted Answer

Substituting $y = 3x - 18$ into the first equation gives $2(3x - 18) + 7x = 68$. Simplifying, we get $6x - 36 + 7x = 68$, which leads to $13x = 104$, so $x = 8$. Substituting $x = 8$ back into $y = 3x - 18$ gives $y = 3(8) - 18 = 24 - 18 = 6$. Therefore, the solution is $x = 8, y = 6$.

Solve, Using the Substitution Method, and Check 2y+7x=68y=3x−18\begin{array} { c } 2 y + 7 x = 68 \\y = 3 x - 18\end{array}2y+7x=68y=3x−18​

Solve, Using the Substitution Method, and Check $\begin{array} { c } 2 y + 7 x = 68 \\y = 3 x - 18\end{array}$