Given the formula: $L = \pi \left( r _ { 1 } + r _ { 2 } \right) + 2 d , L = 56.97 , d = 5.46 , r _ { 2 } = 6$ Find $r_ { 1} $ .
A) $r _ { 1 } = \frac { L - 2 d } { \pi } - r _ { 2 } = 8.76$
B) $r _ { 1 } = \pi ( L - 2 d ) - r _ { 2 } = 139$
C) $r _ { 1 } = \frac { L - 2 d } { \pi } - r _ { 2 } = 8.65$
D) $r _ { 1 } = \frac { L - 2 d } { \pi } - r _ { 2 } = 8.66$
E) $r _ { 1 } = \frac { L } { \pi } + 2 d - r _ { 2 } = 23.1$

Question

Quizplus · Accepted Answer

To find $r_1$, we rearrange the given formula to solve for $r_1$: $r_1 = \frac{L - 2d}{\pi} - r_2$. Substituting the given values, $r_1 = \frac{56.97 - 2(5.46)}{\pi} - 6$, which approximately equals 8.66.

Given the Formula L=π(r1+r2)+2d,L=56.97,d=5.46,r2=6L = \pi \left( r _ { 1 } + r _ { 2 } \right) + 2 d , L = 56.97 , d = 5.46 , r _ { 2 } = 6L=π(r1​+r2​)+2d,L=56.97,d=5.46,r2​=6

Given the Formula $L = \pi \left( r _ { 1 } + r _ { 2 } \right) + 2 d , L = 56.97 , d = 5.46 , r _ { 2 } = 6$