Given the formula: $A = \frac { 1 } { 2 } h ( a + b ) , \quad A = 6,309 , \quad h = 13.0 , \quad b = 546$ Find a.
A) $a = \frac { A } { 2 h } - b = - 303$
B) $a = \frac { 2 A } { h } - b = 425$
C) $a = \frac { A } { 2 ( h - b ) } = 27$
D) $a = \frac { A } { 2 ( h - h ) } = 106$
E) $a = \frac { A } { h } - 2 b = - 607$

Question

Quizplus · Accepted Answer

Plugging in the values given, we get: 
$$6,309 = \frac{1}{2}(13.0)(a+546)$$
$$12,618 = 13.0a+7,098$$
$$5,520 = 13.0a$$
$$a = \frac{5,520}{13.0} = 425$$

Given the Formula A=12h(a+b),A=6,309,h=13.0,b=546A = \frac { 1 } { 2 } h ( a + b ) , \quad A = 6,309 , \quad h = 13.0 , \quad b = 546A=21​h(a+b),A=6,309,h=13.0,b=546

Given the Formula $A = \frac { 1 } { 2 } h ( a + b ) , \quad A = 6,309 , \quad h = 13.0 , \quad b = 546$