Mix a solution that is 60% acid with a solution that is 90% water to make 15 L of a solution that is 30% acid. How much of each solution should you use?
A) So, mix 9 L of the 60% acid solution and 6 L of the 10% acid solution.
B) So, mix 1.5 L of the 60% acid solution and 13.5 L of the 10% acid solution.
C) So, mix 6 L of the 60% acid solution and 9 L of the 10% acid solution.
D) So, mix 4.5 L of the 60% acid solution and 10.5 L of the 10% acid solution.
E) So, mix 7.5 L of the 60% acid solution and 7.5 L of the 10% acid solution.

Question

Quizplus · Accepted Answer

The correct mixture balances the total amount of acid from both solutions to achieve a final concentration of 30% in a 15 L solution. The 90% water solution is equivalent to a 10% acid solution. Using the equation for mixture problems, $0.60x + 0.10(15-x) = 0.30(15)$, where $x$ is the amount of the 60% acid solution, we find $x = 6$ L. Thus, 6 L of the 60% acid solution and 9 L of the 10% acid solution are needed.

Mix a Solution That Is 60% Acid with a Solution