Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c }
2 x - 3 y = 4 \
y = \frac { 2 } { 3 } x - \frac { 4 } { 3 }
\end{array} \right)$$

Question

Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c } 
2 x - 3 y = 4 \
y = \frac { 2 } { 3 } x - \frac { 4 } { 3 }
\end{array} \right)$$

Quizplus · Accepted Answer

The Answer of Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c } 
2 x - 3 y = 4 \
y = \frac { 2 } { 3 } x - \frac { 4 } { 3 }
\end{array} \right)$$

Solve Each System by Using Either the Substitution or the Elimination-By-Addition