Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c }
3 ( x - 1 ) - 4 ( y + 2 ) = 43 \
4 ( x + 2 ) + 3 ( y - 1 ) = - 23
\end{array} \right)$$

Question

Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c } 
3 ( x - 1 ) - 4 ( y + 2 ) = 43 \
4 ( x + 2 ) + 3 ( y - 1 ) = - 23
\end{array} \right)$$

Quizplus · Accepted Answer

The Answer of Solve each system by using either the substitution or the elimination-by-addition method, whichever seems more appropriate. $$\left( \begin{array} { c } 
3 ( x - 1 ) - 4 ( y + 2 ) = 43 \
4 ( x + 2 ) + 3 ( y - 1 ) = - 23
\end{array} \right)$$

Solve Each System by Using Either the Substitution or the Elimination-By-Addition