Solve the equation. $20 x ^ { 2 } + 43 x = - 14$
A) $\left\{ - \frac { 7 } { 4 } , - \frac { 2 } { 5 } \right\}$
B) $\left\{ \frac { 7 } { 4 } , \frac { 2 } { 5 } \right\}$
C) $\left\{ - \frac { 7 } { 4 } , \frac { 5 } { 2 } \right\}$
D) $\left\{ - \frac { 7 } { 4 } , \frac { 2 } { 5 } \right\}$
E) $\left\{ \frac { 7 } { 4 } , - \frac { 2 } { 5 } \right\}$

Question

Quizplus · Accepted Answer

First, rewrite the equation in standard form: $20x^2 + 43x + 14 = 0$. Factoring or using the quadratic formula, we find the solutions to be $x = -\frac{7}{4}$ and $x = -\frac{2}{5}$, which matches option A.

Solve the Equation 20x2+43x=−1420 x ^ { 2 } + 43 x = - 1420x2+43x=−14

Solve the Equation $20 x ^ { 2 } + 43 x = - 14$