Solve the equation. $14 y ^ { 2 } + 23 y = - 3$
A) $\left\{ \frac { 3 } { 2 } , \frac { 1 } { 7 } \right\}$
B) $\left\{ - \frac { 3 } { 2 } , - \frac { 1 } { 7 } \right\}$
C) $\left\{ \frac { 3 } { 2 } , - \frac { 1 } { 7 } \right\}$

Question

Quizplus · Accepted Answer

First, rearrange the equation to standard form: $14y^2 + 23y + 3 = 0$. Using the quadratic formula, $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 14$, $b = 23$, and $c = 3$, we find the roots to be $y = -\frac{3}{2}$ and $y = -\frac{1}{7}$.

Solve the Equation 14y2+23y=−314 y ^ { 2 } + 23 y = - 314y2+23y=−3

Solve the Equation $14 y ^ { 2 } + 23 y = - 3$