Solve the equation. $25 x ^ { 2 } - 60 x + 36 = 0$
A) $\left\{ \frac { 6 } { 5 } , \frac { 5 } { 6 } \right\}$
B) $\left\{ \frac { 5 } { 6 } \right\}$
C) $\left\{ \frac { 6 } { 5 } \right\}$
D) none of these

Question

Quizplus · Accepted Answer

We can solve this equation using the quadratic formula:

$$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

In this case, $a=25$, $b=-60$, and $c=36$. Plugging in these values, we get:

$$x = \frac{60 \pm \sqrt{60^2-4(25)(36)}}{2(25)}$$

Simplifying this expression, we get:

$$x = \frac{60 \pm \sqrt{3600-3600}}{50} = \frac{60}{50} = \frac{6}{5}$$

Therefore, the only solution is $x=\frac{6}{5}$, which is choice C.

Solve the Equation 25x2−60x+36=025 x ^ { 2 } - 60 x + 36 = 025x2−60x+36=0

Solve the Equation $25 x ^ { 2 } - 60 x + 36 = 0$