Solve each equation. Match each equation with the corresponding solution.
-$n = 1.75$
A) $\frac { 5 } { n + 3 } + \frac { 4 } { n - 4 } = \frac { 5 n - 1 } { n ^ { 2 } - n - 12 }$
B) $\frac { 4 } { n + 4 } + \frac { 4 } { n - 5 } = \frac { 4 n - 1 } { n ^ { 2 } - n - 20 }$

Question

Solve each equation. Match each equation with the corresponding solution.
-$n = 1.75$ 
A) $\frac { 5 } { n + 3 } + \frac { 4 } { n - 4 } = \frac { 5 n - 1 } { n ^ { 2 } - n - 12 }$ 
B) $\frac { 4 } { n + 4 } + \frac { 4 } { n - 5 } = \frac { 4 n - 1 } { n ^ { 2 } - n - 20 }$

Quizplus · Accepted Answer

For choice A, simplifying the right side gives $\frac{5n-1}{(n+3)(n-4)}$, which matches the denominators on the left side when $n = 1.75$. For choice B, the denominators and the equation structure do not match when $n = 1.75$.

Solve Each Equation n=1.75n = 1.75n=1.75 A) 5n+3+4n−4=5n−1n2−n−12\frac { 5 } { n + 3 } + \frac { 4 } { n - 4 } = \frac { 5 n - 1 } { n ^ { 2 } - n - 12 }n+35​+n−44​=n2−n−125n−1​

Solve Each Equation $n = 1.75$ A) $\frac { 5 } { n + 3 } + \frac { 4 } { n - 4 } = \frac { 5 n - 1 } { n ^ { 2 } - n - 12 }$