Solve the equation. $\left( 3 ^ { 4 x - 4 } \right) \left( 3 ^ { x + 1 } \right) = 27$
A) $x = - \frac { 6 } { 5 }$
B) $x = \frac { 11 } { 5 }$
C) $x = - \frac { 1 } { 5 }$
D) $x = \frac { 6 } { 5 }$

Question

Quizplus · Accepted Answer

\begin{align*}
\left( 3 ^ { 4 x - 4 } ight) \left( 3 ^ { x + 1 } ight) &= 27 \
3^{4x-4+x+1}&=27 \
3^{5x-3}&= 27 \
3^{5x-3}&= 3^ {3} \
5x-3&= 3 \
x&=\frac{6}{5}
\end{align*}

Thus, the answer is choice D, as it is the only option that includes this value of $x$.

Solve the Equation (34x−4)(3x+1)=27\left( 3 ^ { 4 x - 4 } \right) \left( 3 ^ { x + 1 } \right) = 27(34x−4)(3x+1)=27

Solve the Equation $\left( 3 ^ { 4 x - 4 } \right) \left( 3 ^ { x + 1 } \right) = 27$