Solve the system. $$\left( \begin{array} { r l r }
- 2 x + 3 y + 5 z & = 23 \
3 x - 5 z & = - 13 \
5 z & = 25
\end{array} \right)$$
A) x = 4, y = 2, z = 5
B) x = 5, y = 1, z = 3
C) x = 3, y = -1, z = 3
D) x = 3, y = 0, z = 5

Question

Solve the system. $$\left( \begin{array} { r l r } 
- 2 x + 3 y + 5 z & = 23 \
3 x - 5 z & = - 13 \
5 z & = 25
\end{array} \right)$$
A) x = 4, y = 2, z = 5
B) x = 5, y = 1, z = 3
C) x = 3, y = -1, z = 3
D) x = 3, y = 0, z = 5

Quizplus · Accepted Answer

From the third equation, $5z = 25$, we find $z = 5$. Substituting $z = 5$ into the second equation, $3x - 5(5) = -13$, we find $x = 4$. Substituting $x = 4$ and $z = 5$ into the first equation, we find $y = 2$.

Solve the System (−2x+3y+5z=233x−5z=−135z=25)\left( \begin{array} { r l r } - 2 x + 3 y + 5 z & = 23 \\3 x - 5 z & = - 13 \\5 z & = 25\end{array} \right)​−2x+3y+5z3x−5z5z​=23=−13=25​​

Solve the System $\left( \begin{array} { r l r } - 2 x + 3 y + 5 z & = 23 \\3 x - 5 z & = - 13 \\5 z & = 25\end{array} \right)$