Part of $10,000 is invested at 9%, another part at 11%, and the remainder at 12% yearly interest. The total yearly income from the three investments is $1,100. The sum of the amounts invested at 9% and 11% equals the amount invested at 12%. How much is invested at each rate?
A) $2,500 at 9%, $2,500 at 11%, and $5,000 at 12%
B) $1,500 at 9%, $2,500 at 11%, and $6,000 at 12%
C) $1,500 at 9%, $2,000 at 11%, and $6,000 at 12%
D) $3,000 at 9%, $2,000 at 11%, and $5,000 at 12%

Question

Quizplus · Accepted Answer

The total investment is $10,000, and the total interest earned is $1,100. The sum of the amounts invested at 9% and 11% equals the amount invested at 12%, which means if x is the amount at 12%, then the amount at 9% and 11% combined is also x, making the total investment 2x = $10,000, so x = $5,000. Given the total interest and the rates, the distribution that meets these conditions while also achieving the total interest of $1,100 is $2,500 at 9%, $2,500 at 11%, and $5,000 at 12%.

Part of $10,000 Is Invested at 9%, Another Part at 11