The heat of vaporization of water is 540 cal/g. What mass of water at 100.0 °C can be vaporized by the addition of 55.0 kcal of heat?

Question

Quizplus · Accepted Answer

To solve this problem, we can use the formula:

q = m*ΔH

where q is the amount of heat added, m is the mass of water, and ΔH is the heat of vaporization of water.

We are given q = 55.0 kcal and ΔH = 540 cal/g. We can convert the heat added to calories:

55.0 kcal * 1000 cal/kcal = 55,000 cal

Substituting these values into the formula, we get:

55,000 cal = m * 540 cal/g

Solving for m:

m = 102.04 g

Therefore, the mass of water that can be vaporized is 102.04 g.

The best choice is D, 102 g.

The Heat of Vaporization of Water Is 540 Cal/g