The time required for a dropped object to hit the ground is given by $t = \sqrt { \frac { 2 h } { g } }$ , where h is the vertical distance traveled and g is the acceleration due to gravity (32.2 feet per second squared). How long will it take an object to fall from the top of the Torre Commercial America, in Monterrey, Mexico at 427 feet tall? Round the answer to the nearest tenth.
A) t = 26.5 sec.
B) t = 5.1 sec.
C) t = 10.9 sec.
D) t = 5.7 sec.
E) t = 6.4 sec.

Question

Quizplus · Accepted Answer

Using the formula $t = \sqrt { \frac { 2 h } { g } }$ with $h = 427$ feet and $g = 32.2$ feet per second squared, the calculation is $t = \sqrt { \frac { 2 \times 427 } { 32.2 } } \approx 5.1$ seconds.

The Time Required for a Dropped Object to Hit the Ground