Simplify the expression. Remove all negative and zero exponents. Assume the expression is defined. $\left( \frac { 2 c } { a ^ { 4 } b } \right) ^ { - 3 }$
A) $\frac { 8 c } { a ^ { 4 } b }$
B) $\frac { a ^ { 12 } b ^ { 3 } } { 8 c ^ { 3 } }$
C) $\frac { 2 c } { a ^ { 4 } b }$
D) $\frac { 8 c ^ { 3 } } { a ^ { 12 } b ^ { 3 } }$
E) $\frac { a ^ { 12 } b ^ { 3 } } { 2 c ^ { 3 } }$

Question

Quizplus · Accepted Answer

When you raise a fraction to a negative exponent, you invert the fraction and change the sign of the exponent. Thus, $\left( \frac { 2 c } { a ^ { 4 } b } \right) ^ { - 3 }$ becomes $\left( \frac { a ^ { 4 } b } { 2 c } \right) ^ { 3 }$. When you raise both the numerator and the denominator to the 3rd power, you get $\frac { a ^ { 12 } b ^ { 3 } } { 8 c ^ { 3 } }$.

Simplify the Expression (2ca4b)−3\left( \frac { 2 c } { a ^ { 4 } b } \right) ^ { - 3 }(a4b2c​)−3

Simplify the Expression $\left( \frac { 2 c } { a ^ { 4 } b } \right) ^ { - 3 }$