Solve: $$3 x - 4 \geq 4 x + 6$$ A) $x \geq - 10$ B) $x - 10$ C) $x \leq - 10$ D) $x

Name: Solve: \[3 x - 4 \geq 4 x + 6\] A) $x \geq - 10$ B) $x > - 10$ C) $x \leq - 10$ D) $x < - 10$ E) No solutions exist
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Question

Solve: $$3 x - 4 \geq 4 x + 6$$
A) $x \geq - 10$
B) $x > - 10$
C) $x \leq - 10$
D) $x < - 10$
E) No solutions exist

Quizplus · Accepted Answer

Subtracting $4x$ from both sides gives $-x - 4 \geq 6$, and adding $4$ to both sides gives $-x \geq 10$. Multiplying both sides by $-1$ and reversing the inequality sign gives $x \leq -10$.

Solve 3x−4≥4x+63 x - 4 \geq 4 x + 63x−4≥4x+6 A) x≥−10x \geq - 10x≥−10

Solve $3 x - 4 \geq 4 x + 6$ A) $x \geq - 10$