Solve the system by any method, if possible. $$\left\{ \begin{array} { l }
x = \frac { 3 } { 2 } y + 3 \
2 x - 3 y = 9
\end{array} \right.$$
A) $\left( \frac { 1 } { 2 } , 12 \right)$
B) $\left( 12 , \frac { 3 } { 2 } \right)$
C) $\left( 9 , \frac { 2 } { 3 } \right)$
D)infinitely many solutions, dependent equations
E)no solution, inconsistent system

Question

Solve the system by any method, if possible. $$\left\{ \begin{array} { l } 
x = \frac { 3 } { 2 } y + 3 \
2 x - 3 y = 9
\end{array} \right.$$
A) $\left( \frac { 1 } { 2 } , 12 \right)$
B) $\left( 12 , \frac { 3 } { 2 } \right)$
C) $\left( 9 , \frac { 2 } { 3 } \right)$
D)infinitely many solutions, dependent equations
E)no solution, inconsistent system

Quizplus · Accepted Answer

The Answer of Solve the system by any method, if possible. $$\left\{ \begin{array} { l } 
x = \frac { 3 } { 2 } y + 3 \
2 x - 3 y = 9
\end{array} \right.$$
A) $\left( \frac { 1 } { 2 } , 12 \right)$
B) $\left( 12 , \frac { 3 } { 2 } \right)$
C) $\left( 9 , \frac { 2 } { 3 } \right)$
D)infinitely many solutions, dependent equations
E)no solution, inconsistent system

Solve the System by Any Method, If Possible {x=32y+32x−3y=9\left\{ \begin{array} { l } x = \frac { 3 } { 2 } y + 3 \\2 x - 3 y = 9\end{array} \right.{x=23​y+32x−3y=9​

Solve the System by Any Method, If Possible $\left\{ \begin{array} { l } x = \frac { 3 } { 2 } y + 3 \\2 x - 3 y = 9\end{array} \right.$