Find a true inequality that involves the real number $\frac { 11 } { 6 }$ . A) $\frac { 11 } { 6 } \frac { 11 } { 8 }$ C) $\frac { 11 } { 6 } \frac { 17 } { 6 }$ D) $\frac { 11 } { 6 }

Question

Find a true inequality that involves the real number $\frac { 11 } { 6 }$ . A) $\frac { 11 } { 6 } < \frac { 5 } { 6 }$ B) $\frac { 11 } { 6 } > \frac { 11 } { 8 }$ C) $\frac { 11 } { 6 } > \frac { 17 } { 6 }$ D) $\frac { 11 } { 6 } < \frac { 11 } { 9 }$ E) $\frac { 11 } { 6 } < - \frac { 17 } { 6 }$

Quizplus · Accepted Answer

$\frac { 11 } { 6 }$ is greater than $\frac { 11 } { 8 }$ because when comparing fractions with the same numerator, the fraction with the smaller denominator is larger.

Find a True Inequality That Involves the Real Number 116\frac { 11 } { 6 }611​

Find a True Inequality That Involves the Real Number $\frac { 11 } { 6 }$