Compete the table and use the results to sketch the graph of the equation $y = | x - 1 |$ .
$\begin{array} { | l | l | l | l | l | l | }
\hline x & - 2 & - 1 & 0 & 1 & 2 \
\hline y & & & & & \
\hline
\end{array}$

Question

Compete the table and use the results to sketch the graph of the equation $y = | x - 1 |$ . 
$\begin{array} { | l | l | l | l | l | l | } 
\hline x & - 2 & - 1 & 0 & 1 & 2 \
\hline y & & & & & \
\hline
\end{array}$

Quizplus · Accepted Answer

To complete the table, we need to substitute each given value of x, one at a time, into the equation $y = | x - 1 |$, and evaluate.
For $x=-2$, $y = | -2 - 1 | = 3$
For $x=-1$, $y = | -1 - 1 | = 2$
For $x=0$, $y = | 0 - 1 | = 1$
For $x=1$, $y = | 1 - 1 | = 0$
For $x=2$, $y = | 2 - 1 | = 1$
Now we can plot these points on the coordinate plane and sketch the graph of $y = | x - 1 |$. The graph is symmetric about the vertical line $x = 1$, and consists of two segments: one with a slope of 1, passing through (1, 0), and another with a slope of -1, passing through (0, 1). The graph looks like a "\V/" shape with its vertex at (1,0), as shown in choice D.

Compete the Table and Use the Results to Sketch the Graph