The table shows the projected number N (in millions)of persons with pets in a certain country. $$\begin{array} { | c | c | c | c | c | }
\hline \text { Year } & 2010 & 2015 & 2020 & 2025 \
\hline N & 39.15 & 47.8 & 56.81 & 65.96 \
\hline
\end{array}$$ A model for this data is $N = 1.83 t + 20.9$ where t represents time in years, with $t = 10$ corresponding to the year 2010. According to the model, in what year will the number of pet owners exceed $72.14$ million?
A) $2034$
B) $2029$
C) $2024$
D) $2027$
E) $2028$

Question

The table shows the projected number N (in millions)of persons with pets in a certain country. $$\begin{array} { | c | c | c | c | c | } 
\hline \text { Year } & 2010 & 2015 & 2020 & 2025 \
\hline N & 39.15 & 47.8 & 56.81 & 65.96 \
\hline
\end{array}$$ A model for this data is $N = 1.83 t + 20.9$ where t represents time in years, with $t = 10$ corresponding to the year 2010. According to the model, in what year will the number of pet owners exceed $72.14$ million?
A) $2034$
B) $2029$
C) $2024$
D) $2027$
E) $2028$

Quizplus · Accepted Answer

To find when the number of pet owners exceeds 72.14 million, set $N = 72.14$ and solve for $t$: $72.14 = 1.83t + 20.9$. Solving gives $t \approx 18.5$. Since $t = 10$ corresponds to 2010, $t = 18.5$ corresponds to 2018.5, which is in the year 2028.

The Table Shows the Projected Number N (In Millions)of Persons