Write an equation for a line that passes through (8,-8) and is perpendicular to $5 x + 8 y = 26$ .
A) $y = - \frac { 5 } { 8 } x - \frac { 56 } { 5 }$
B) $y = - \frac { 5 } { 8 } x - \frac { 104 } { 5 }$
C) $y = - \frac { 8 } { 5 } x - \frac { 104 } { 5 }$
D) $y = \frac { 5 } { 8 } x + \frac { 104 } { 5 }$
E) $y = \frac { 8 } { 5 } x - \frac { 104 } { 5 }$

Question

Quizplus · Accepted Answer

The slope of the line $5x + 8y = 26$ is $-\frac{5}{8}$. A line perpendicular to it will have a slope of $\frac{8}{5}$. Using the point-slope form with point (8, -8), the equation is $y + 8 = \frac{8}{5}(x - 8)$, which simplifies to $y = \frac{8}{5}x - \frac{104}{5}$.

Write an Equation for a Line That Passes Through (8,-8) 5x+8y=265 x + 8 y = 265x+8y=26

Write an Equation for a Line That Passes Through (8,-8) $5 x + 8 y = 26$