Factor the expression by factoring out the common binomial factor. $( 2 x - 3 ) ( x + 5 ) + ( 7 x + 1 ) ( x + 5 )$
A) $( 9 x - 2 ) ( 2 x - 3 )$
B) $( 2 x - 3 ) ( 7 x + 1 )$
C) $( 7 x + 1 ) ( x + 5 )$
D) $( 9 x - 2 ) ( x + 5 )$
E) $( 2 x - 3 ) ( x + 5 )$

Question

Quizplus · Accepted Answer

The common binomial factor in both terms is $(x + 5)$, so when factored out, the expression becomes $(2x - 3 + 7x + 1)(x + 5)$, which simplifies to $(9x - 2)(x + 5)$.

Factor the Expression by Factoring Out the Common Binomial Factor (2x−3)(x+5)+(7x+1)(x+5)( 2 x - 3 ) ( x + 5 ) + ( 7 x + 1 ) ( x + 5 )(2x−3)(x+5)+(7x+1)(x+5)

Factor the Expression by Factoring Out the Common Binomial Factor $( 2 x - 3 ) ( x + 5 ) + ( 7 x + 1 ) ( x + 5 )$