Solve the equation. $\frac { z + 2 } { 3 } = 5 - \frac { z } { 15 }$
A) $z = \frac { 70 } { 3 }$
B) $z = \frac { 101 } { 6 }$
C) $\text { Time varies directly as the distance and inversely as the average speed. }$
D) $z = \frac { 14 } { 3 }$
E) $z = \frac { 65 } { 6 }$

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The Answer of Solve the equation. $\frac { z + 2 } { 3 } = 5 - \frac { z } { 15 }$
A) $z = \frac { 70 } { 3 }$
B) $z = \frac { 101 } { 6 }$
C) $\text { Time varies directly as the distance and inversely as the average speed. }$
D) $z = \frac { 14 } { 3 }$
E) $z = \frac { 65 } { 6 }$

Solve the Equation z+23=5−z15\frac { z + 2 } { 3 } = 5 - \frac { z } { 15 }3z+2​=5−15z​

Solve the Equation $\frac { z + 2 } { 3 } = 5 - \frac { z } { 15 }$